if p(x,y) is equdistant from the pts A(6,-1) and B (2,3) show that x-y = 3
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Answer:
PA=PB
squaring on both sides
PA^2=PB^2
Using distance formula
(x-6)^2+(y+1)^2=(x-2)^2+(y-3)^2
x^2+36-12x+y^2+1+2y=x^2+4-4x+y^2+9-6y
8x-8y=24
8(x-y)=24
x-y=3
Hence proved
Mahijaan:
Thanks for marking my answer as brain list
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