Question

if p(x,y) is equidistant from q(-2,5) & r(6,-1) find relation ship between x & y

Answer 1

m=1
m'=1
x=-2
x'=6
y=5
y'=-1
using distance formula
(m×x'+m'×x)/(m+m')=x
(6-2)/2=x
2
(m×y'+m'×y)/(m+m')=y
(-1+5)/2=y
2=y