Question

If p = x+y-z, q= y+z-x, r = x+z-y then prove that p³+q³+r³ - 4(x³+y³ + z³) = 3(pqr - 4xyz)

Answer 1

Your answer.......

1)p=x+y-z

1=2+3-4

1=5-4

1=1 it is true

2)q=y+z-x

5=3+4-2

5=7-2

5=5 it is true

3)r=x+z-y

3=2+4-3

3=6-3

3=3 it is true

p³+q³+r³-4(x³+y³+z³)=3(pqr-4xyz)

=1×1×1+2×2×2+3×3×3-4(1×1×1+2×2×2+3×3×3)=3(1×2×3-4×5× 6×7)

=1+8+9-4(1+8+9)=3(6-840)

=14+18=3+834

=32=837 it is not true

These your answer...........