Math, asked by heybuddy299, 8 months ago

If P= x2 – 2x + 3 and
Q = x2 – 5,
then what is the value of PQ.
(a) x4 – 2x3 + 3x2 – 15
(b) x4 – 2x3 - 2x2 + 10x - 2
(c) x4 – 2x3 + 3x2 + 10x – 15
(d) x4 – 2x3 – 2x2 + 10x – 15
please tell the answer with full explanation​

Answers

Answered by gmhingangavkar
2

Answer:

PQ= x⁴-2x³-2x²+10x-15

Step-by-step explanation:

Given P= x²-2x +3 and

Q= x²-5

To find PQ,

consider,

PQ = (x²-2x +3)×(x²-5)

PQ= (x²-5)x²+(x²-5)(-2x)+3(x²-5)

PQ= x⁴-5x² -2x³+10x+3x²-15

PQ= x⁴-2x³-2x²+10x-15

this is the required answer.

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