Math, asked by sfhikvshndgnm, 2 months ago

If P = x³y² and Q = 3x²yz² , then HCF(P , Q) =

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Answered by s22705

0

Answer:

7 If two positive integers p and q are written as p = a2b3 and q = a3b; a, b are prime numbers, then verify: LCM (p, q) HCF (p, q) ...

Missing: x³y² ‎3x²yz² ,

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