Question

If (p)=xsquare+3x+1 then find p(0) p(-1)

Answer 1

Step-by-step explanation:

$p(x) = {x}^{2} + 3x + 1 \\ p(0) = {0}^{2} + 3(0) + 1 </p><p>= 0 + 0 + 1 = 1 \\ p( - 1) = { (- 1)}^{2} + 3( - 1) + 1</p><p> = 1 - 3 + 1</p><p> = - 1$

Answer 2

Step-by-step explanation:

p(x)=x^2+3x+1

p(0)=(0)^2+3(0)+1

p(0)=0+0+1

p(0)=1

p(x)=x^2+3x+1

p(-1)=(-1)^2+3(-1)+1

p(-1)=1-3+1

p(-1)= -1

p(0)×p(-1)=1× -1= -1