If p(y) =2y+7, then find the value of p(1), p(0) and p(-1).
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1
Answer:
9, 7, 5
Step-by-step explanation:
p(1)= 2(1)+7= 2+7=9
p(0)= 2(0)+7=0+7=7
0(-1)= 2(-1)+7=5
Answered by
0
Answers: P(1)= 2(1)+7= 9
P(0)= 2(0)+7= 7
P(-1)=2(-1)+7= 5
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