Question

If p(y)=2y2-√2y+2 then p(√2)=​

Answer 1

Answer:

4

Step-by-step explanation:

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Answer 2

Answer:

$p( y ) = 2 {y}^{2} - \sqrt{2} y + 2$

$p( \sqrt{2} ) = 2 {( \sqrt{2}) }^{2} - \sqrt{2} \times \sqrt{2} + 2$

$p( \sqrt{2} ) = 2 \times 2 - 2 + 2$

$p( \sqrt{2} ) = 4 - 2 + 2$

$p( \sqrt{2} ) = 6 - 2$

$p( \sqrt{2} ) = 4$