Question

if p(y)=2y³-6y²-5y+7 then find p(-2)​

Answer 1

Answer:

Q) p(y) =2y^3-6y^2-5y+7

p(-2)

p(-2) =2(-2)^3-6(-2)^2-5(-2)+7

= -16-24+10+7

= -23

Therefore, value of p(-2) is -23.

Answer 2

Answer:

-23

Step-by-step explanation:

p(-2)=2(-2)^3-6(-2)^2-5(-2)+7

=2(-8) -6(4) +10+7

=-16-24+17

=-40+17

=-23

hope it helped u

please mark as brainliest if it helped

thank u