Question

If p( y)= 2y³ - 6y² -5y + 7 then find p(2) & p (0).​

Answer 1

p(2)=2*8-6*4-5*2+7=-11

p(0)=7

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Answer 2

Answer:

p(y)=2y^3-6y^2-5y+7

(1). p(2)=2×2^3-6×2^2-5y+7

=2×8-6×4-5×2+7

=16-24-10+7

=23-34

= -11 ans

2. p(0)=2×0^3-6×0^2-5×0+7

=2×0-6×0-5×0+7

=7ans