Math, asked by kausamir0075, 10 months ago

If p( y)= 2y³ - 6y² -5y + 7 then find p(2) & p (0)

please fast and correct and I will mark you as a brainlist​

Answers

Answered by MrSmartGuy1729
25

Answer:

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  • Since p(2) = 2×2^3-6×2^2+7

------> 16-24+7

16+7-24 = -1

Since p(0) = 2×0^3-6×0^2+7

----> 0+0+7

p(0) = 7 and p(2) = -1

Answered by ZzyetozWolFF
50

Answer:

  • p(2) = -11

  • p(0) = 7

Step-by-step explanation:

  • Finding value of p at 2.

 \implies \: p(2) = 2 {(2)}^{3}  - 6 {(2)}^{2}  - 5(2) + 7

 \implies \: p(2) = 2(8) - 6(4) - 10 + 7

 \implies \: p(2) = 16 - 24 - 10 + 7

 \implies \: p(2)  = - 11

  • Finding the value of p at 0.

 \implies \: p(0) = 2 {(0)}^{3}  - 6(0) - 5(0) + 7

 \implies \: p(0) = 2(0) - 6(0) - 5(0) + 7

 \implies \: \: p(0) =  0 - 0 - 0 + 7

 \implies \: p(0) = 7

Polynomials :-

  • polynomials : Polynomial are variable based dialect in the language of maths.

  • In a common language , polynomials are defined as a string of variables and numbers put together.

  • Highest power of a polynomial is called degree of polynomial.

  • A constant polynomial is nothing but a monomial with degree zero.

  • Equation: A condition or a constraint placed on x and y coordinates.

  • Curve: A union of points that satisfy a particular condition.

  • Remainder theorem: When p(x) is divided by (x - a) then the remainder is given by p(a).

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