Question

If p (y)=2y4 -y3+2y2+6 then p(-1) will be.

Answer 1

Answer:

I hope you find the solution in the photo useful.

Answer 2

Answer:

Required value of p(-1) is 11

Explanation:

Given,

$p(y) = 2 {y}^{4} - {y}^{3} + 2 {y}^{2} + 6$

Here we want to find value of p(-1).

By value putting we can find the answer.

For example,

We are putting y=2 and get,

$p(2) = 2 {(2)}^{4} - {2}^{3} + 2 ({2)}^{2} + 6 \\ p(2) = 2 \times 16 - 8 + 2 \times 4 + 6 \\ = 32 - 8 + 8 + 6 \\ = 38$

So, value of p(2) is 38.

Here we want to find p(-1),

So we are putting y=(-1) and get,

$p( - 1) = 2 {( - 1)}^{4} - {( - 1)}^{3} + 2 {( - 1)}^{2} + 6 \\ = 2 \times 1 - ( - 1) + 2 + 6 \\ = 2 + 1 + 2 + 6 \\ = 11$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549