Question

If p(y)=3+2y-y2+6y3 find p(0)

Answer 1

...................hope it helps u mate.............. .

Answer 2

Answer :-

$\bf\huge\boxed{3}$

Solution :-

If p(y)=3 + 2y - y² +6y³, find p(0)

Putting the value of y in p(y)= 3 + 2y - y² +6y³

=3 + 2y - y² +6y³

= 3 + 2 × 0 - (0)² + 6 × (0)³

= 3 + 0 - 0 + 6 × 0

= 3 + 0

= 3

Hence, the remainder is 3