Question

if p(y) =4 +3y -y^2+5y^3 find p(0) p (2) p(-1)​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

SOLUTION

p(y) = 4 + 3y - y² + 5y³

1) p(0) = 4 + 3(0) - (0)² + 5(0)³

p(0) = 4 + 0 - 0 + 0

p(0) = 4

2) p(2) = 4 + 3(2) - (2)² + 5(2)³

p(2) = 4 + 6 - 4 - 5(8)

p(2) = 10 - 44

p(2) = -34

3) p(-1) = 4(-1) - (-1)² + 5(-1)³

p(-1) = -4 -(1) + 5(-1)

p(-1) = - 4 - 1 - 5

p(-1) = -10