Question

if p(y)=4+3y-y2+5y3. find. p(0) p(2) p(-1).

Answer 1

Hello there,

Put formula p(y)=4+3y-y2+5y3 and the value of y = 0, y=2 and y=-1

P(0)= 4

P(2)= 30

P(-1)=7

I hope you like the answer

Answer 2

Hey buddy.....!! here is ur answer

Given that....p(y) = 4+3y-y²+5y³

p(y) = 5y³-y²+3y+4

On putting y = 0, then

p(0) = 5(0)³-(0)²+3(0)+4

=> p(0) = 4

Now, on putting y = 2, then

p(2) = 5(2)³-(2)²+3(2)+4

=> p(2) = 5×8-4+6+4

=> p(2) = 46

Again, on putting y = -1 then

p(-1) = 5(-1)³-(-1)²+3(-1)+4

=> p(-1) = -5-1-3+4

=> p(-1) = -5

Therefore, required value of p(0) = 4, p(2) = 46 and p(-1) = -5

I hope it will be helpful for you......!!

THANK YOU ✌️✌️

MARK IT AS BRAINLIEST