Question

if p(y) = 4+3y-y2+5y3,find( p-1)

Answer 1

Given:

• $p(y)=4+3^y-y^2+5y^3$

To Find:

• Value of polynomial  p(-1)

 

Solution:

      ⇒     $p(y)=4+3^y-y^2+5y^3$

Rearranging the polynomial

      ⇒    $p(y) =5y^3-y^2+3y+4$

Put  $y = -1$ in the polynomial

     ⇒     $p(-1) =5(-1)^3-(-1)^2+3(-1)+4$

     ⇒      $p(-1) =5(-1) -1 -3+4$

     ⇒      $p(-1) = -5 -1 -3+4$

     ⇒      $p(-1) = -9+4$

     ⇒      $p(-1) = -5$

Thus, the value of $p(-1) \ is \ - 5$

Answer 2

Answer:

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