Question

if p(Y) =4+3Y-Y²+5Y³, FIND P(2)​

Answer 1

Step-by-step explanation:

$p(y) = 4 + 3y -{y}^{2} + 5 {y}^{3} = >$

$p(2) = 4 + 3(2) - {(2)}^{2} + 5 {(2)}^{3} = >$

$p(2) = 4 + 6 - 4 + 40 = > p(2) = 46$

Hope it helps you.

Answer 2

$p(y) = 4 + 3y - y {}^{2} + 5y {}^{3}$

$p(2) = 4 + 3(2) - (2) {}^{2} + 5(2) {}^{3}$

$p(2) = 4 + 6 - 4 + 40$

$p(2) = 50 - 4$

$p(2) = 46$