Question

if p(y)=y^2+5y+4,find the value of p[-1] and p[1].​

Answer 1

Answer:

0 and 10

Step-by-step explanation:

p(-1) = (-1)^2+5(-1)+4 = 1-5+4 = 0

p(1) = (1)^2+5(1)+4 = 1+5+4 = 10

Answer 2

Answer:

given that

p(y)=y²+5y+4

p(-1)=(-1)²+5(-1)+4

=1 - 5 + 4

=0

p(1)=1²+5(1)+4

=1 + 5 + 4

= 10