if p(y)=y^2-y+1,then find the value of (i)p(1) (ii)p(2)
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Answer:
p(1) = 1^2 - 1 + 1
= 1 - 1 + 1
= 1
p(2) = 2^2 - 2 + 1
= 4 - 2 + 1
= 2 + 1
= 3
... hope it helps you.....
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