Math, asked by shinyraj, 8 months ago

if p(y)=y^2-y+1 then p(1)=​

Answers

Answered by ss221085
0

subtitute y=1

we get,

p(1)= 1^2 -1+1

p(1)= 1-1+1

p(1)=0+1

p(1)=1

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