Question

if p(y) =y^2-y+1 then the value of p(2)is​

Answer 1

Solution:

It is given that,

p(y) = y²-y+1

Substitute y = 2 in p(y), we get

Value of p(2) = 2²-2+1

= 4-2+1

= 2+1

= 3

Therefore,

p(2) = 3

••••

Answer 2

Answer:

Step-by-step explanation: