Question

if p(y) = y^2-y+y then p(2)=

Answer 1

$\underline{\bold{Answer:-}}$



$\\ p(y) = y {}^{2} - y + y \\ \\when \: \: y = 2 \\ \\ p(2) = 2 {}^{2} - 2 + 2 \\ \\ = > 4 - 2 + 2 \\ \\ = > 6 - 2 \\ \\ = > 4$






$\textbf{Hope it helps!}$

Answer 2

hey!

here is answer

p(y)= y^2-y+y

to find p(2)


p(2)=2^2-2+2

p(2)=4-2+2

p(2)=4 answer

hope it helps

thanks