Math, asked by deepika469462, 7 months ago


if p(y) = y – 3 √2 y + 1 then find p (3√2).​

Answers

Answered by REDNINJA
5

Answer:

p(y) = y – 3√2y + 1

   

p(3√2) = 3√2 – (3√2)(3√2) + 1

            = 3√2 - 18 + 1

            = 3√2 - 17

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Answered by shivi7617
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Answer:

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