Question

if p(y) =y^3+2y^2-3, then find the value of p(1) and p(0) .​

Answer 1

Answer:

p(1)=0,  p(0)= -3

Step-by-step explanation:

p(1)=1³+2(1)²-3=0

p(0)=0³+2(0)²-3= -3