if p(y)=y square _2y+5 find p(2)
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solution :-
p(y)=y^2-2y+5
then find the value of p(2) substitute y=2,
p(2)=2^2-2×2+5
p(2)=4-4+5
p(2)=0+5
p(2)=5
---------------
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p(y)=y^2-2y+5
then find the value of p(2) substitute y=2,
p(2)=2^2-2×2+5
p(2)=4-4+5
p(2)=0+5
p(2)=5
---------------
hope it will be helpful
plzz mark me as brain list plzz
plzz
plzz
plzz
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