Question

if p(y) = y(y-1)(y+2) then the value of p(0)+p(1)+ p(-2) is
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Answer 1

Step-by-step explanation:

The answer is in figure........

Answer 2

Answer:

zero.

Step-by-step explanation:

p(0) = 0(0-1)(0+2)

= 0

p(1).= 1(1-1)(1+2)

= zero

p(2)= 2(2-1)(2-2)

= 0

and hence p(0) + p(1) + p(2)= 0+0+0

= 0