Question

if p(y)=y²-3 2+1=then find p(3 2)​

Answer 1

Answer:

Given

⇒P(y)=y

2

−3

2y

+1

⇒P(3

2

)=(3

3

)

2

−3

2.(2)

2

1

+1

=(2)

3

2

−3(2

1+

3

1

)

2

1

+1

=2

3

2

−3

3

4

×

2

1

+1

=2

3

2

−3.2

3

2

+1

=−2.2

3

2

+1

=−2

3

2

+1

+1

=1−2

3

5

Answer 2

hope this wil help u..!!

#loki