If p(y)=y²-3√2y+1 the find p(3√2). *
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Step-by-step explanation:
= p(y)= p(3√2)
= y= 3√2
= 3√2= y२-3√2y+1
= 3√2+3√2= y२+1
= 6√2= y२+1
= y२+1-6√2
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