Question

if p(y)=y2-3√3y+1,then find p(3√3)​

Answer 1

$\mathfrak{\huge{Answer:}}$

Here, in this question, we're given the value of the equation :-

p (y) = $\tt{y^{2} - 3\sqrt3 y + 1}$

When we need to find the value of p ($\tt{3\sqrt3}$), it just simply means that we need to keep the value of y = $\tt{3\sqrt3}$. And this value will be kept in the equation which is already given to us. Doing the same, as stated, we get :-

=》 $\sf{(3\sqrt 3)^{2} - 3\sqrt3 (3\sqrt3) + 1}$

Solve this formed equation further

=》 $\sf{27 - 27 + 1}$

Solve this further

=》 $\bold{1}$

Thus, p ($\tt{3\sqrt3}$) = 1