Math, asked by deepanshulohat02, 9 months ago

if p(y)=y3+2y3,then find the value of p(1) and p(0)​

Answers

Answered by Anonymous
0

Answer:

p(1)=3

p(2)=0

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Answered by dharun1
1

Answer:

p(1)=3 and p(0)=0

Step-by-step explanation:

 {y}^{3}  + 2 {y}^{3}  = p(y) \\  \\ p(1) =  {1}^{3}  +2  ({1}^{3} ) \\  = 1 + 2 = 3 \\  \\ p(0) =  {0}^{3}  + 2( {0}^{3} ) = 0 + 0  \\ = 0

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