if p (y) =y³-4y²+6 then show that p (3) =0
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Class 9
>>Maths
>>Polynomials
>>Remainder Theorem
>>By Remainder Theorem find the remainder,
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By Remainder Theorem find the remainder, when p(x) is divided by g(x), wherep(x)=x
3
−6x
2
+2x−4, g(x)=1−
2
3
x
Medium
Solution
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p(x)=x
3
−6x
2
+2x−4 and
g(x)=1−
2
3
x
1−
2
3
x=0
=>
2
3
x=1
=>x=
3
2
By, remainder theorem, the remainder when p(x) divided by g(x) is p(
3
2
)
Thus,
p(
3
2
)=(
3
2
)
3
−6(
3
2
)
2
+2(
3
2
)−4
=
27
8
−
9
6×4
+
3
4
−4
=
27
8
−
9
8
+
3
4
−4
=
27
8−24+36−108
=
27
−136
Hope it helps you ☺️❤️
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