Question

If p(y)=ysquare-y+1 find valuve of p(2)-p(1)-p(0)?

Answer 1

Answer:

Step-by-step explanation:

P(y)=y^2-y+1

P(2)-p(1)-p(0)=(2^2-2+1)-(1-1+1)+1

=1-1+1=1