if p°A & P°B are 108 and 36 torr respectively.What will be the mole fraction of A is the vapour phase if B has mole fraction in solution 0.5
Answers
Answered by
96
Hello Dear,
◆ Answer -
Mole fraction of A in vapour phase = 0.75
● Explanation -
In the solution, total pressure will be -
P = XA.p°A + XB.p°B
P = 0.5 × 108 + 0.5 × 36
P = 72 torr
Mole fraction of A in vapour phase -
XA' = XA.p°A / P
XA' = 0.5 × 108 / 72
XA' = 0.75
Therefore, mole fraction of A in vapour phase is 0.75 .
Hope this helped you.
Answered by
73
Applying Roult's law,
Total Vapour Pressure of the solution = Pa + Pb
= P°a × Xa + P°b × Xb
= 108 × (1 - Xb) + 36 × Xb
= 108 × (1 - 0.5) + 36 × 0.5
= 108 × 0.5 + 36 × 0.5
= 54 + 18
= 72 torr.
Now, Mole Fraction in Vapour Pressure,
Applying Dalton's law,
Partial vapor pressure = Total Vapour Pressre × Xa
108 × 0.5 = 72 × Xa
Xa = 54/72
∴ Xa = 0.75
Hope it helps.
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