Question

If p1 and p2 are two odd prime numbers such that p1 > p2, then p12 p22 is

Answer 1

Step-by-step explanation:

Given  

If p1 and p2 are two odd prime numbers such that p1 > p2, then

p1^2 – p2^2 is

• Let us consider P1 = 7 and p2 = 5
• Then  p1^2 – p2^2
•       = 7^2 – 5^2
•       = 49 – 25
•         = 24
• Now 24 is an even number.
• P1 = 5 and p2 = 3
•       = 5^2 – 3^2
•       = 25 – 9
•       = 16
• Therefore p1^2 – p2^2 is always even for any n

Reference link will be

https://brainly.in/question/386541

Answer 2

• Let us take the two odd prime numbers, as

$p_{1} = 5 \: \\ and \: \\ p_{2} = 3$

• Now, the difference of their squares

( as in question) ,

is 2

Hence the answer is even number.