If P1,P2,....Pn and n statements, then there are P1,P2,....Pn
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To show (p ∧ q) → (p ∨ q). If (p ∧ q) is true, then both p and q are true, so (p ∨ q) is true, and T→T is true. If (p ∧ q) is false, then (p ∧ q) → (p ∨ q) is true, because false implies anything.
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