Question

if p2+8p+19=(p+4)2+b2 then b=​

Answer 1

Answer:

p² + 8p +19 = (p + 4) 2+ b²

==> p² + 8p + 19 = 2p + 8 + b²

==> p² + 8p -2p + 19 -8 = b²

==> p² +6p + 11 = b²

therefore, b =√p² +6p +11

Answer 2

Step-by-step explanation:

p^2+8p+19=2p+8+b^2

p^2+6p+11=b^2

b=√p^2+6p+11 or -√p^2+6p+11

or

p^2+8p+19=(p+4)^2+b^2

(p+4)^2+(√3)^2=(p+4)^2+b^2

b=√3 or b=-√3