Question

If p² x² – q² = 0, then x =? * a. ± q/p b. ±p/q c .p d. q

Answer 1

Answer:

p²x² - q² = 0

(px)² - q² = 0

(px)² = 0 + q²

(px)² = q²

Taking square root on both sides,

$\sqrt{ {(px)}^{2} } \: = \: \sqrt{ {q}^{2} }$

± px = ± q

x = ± q/p

Therefore the answer is Option a.