Question

If p2x2 + (p2 + q2)x + q2 = 0 has equal roots, then p2– q2 is equal to :
(a) – 2q²
(b) 2q²
(c) 0
(d) -1

Answer 1

Answer:

C) 0

Step-by-step explanation:

Equal roots basically means Discriminant D=0

This implies b^2-4ac=0

Here, b=p^2+q^2

a=p^2

c=q^2

(p^2+q^2)^2=4(p^2)(q^2)

On solving, p^2-q^2=0

Thank u

Answer 2

Answer:

p²-q² =0

Step-by-step explanation:

Concept

For a given quadratic equation ax2 + bx + c = 0, the values of x that fulfill the equation are referred to as its roots. i.e., they're the values of the variable (x) which satisfies the equation. The roots of a quadratic characteristic are the x-coordinates of the x-intercepts of the characteristic.

given

p²x² + (p²+ q²)x + q² = 0

it has an equal roots

To find

we have to find the value of p²-q²

solution

as it has equal roots, b²-4ac=0  

so p⁴ + q⁴ + 2P²Q² - 4P²Q²=0

or p⁴ + q⁴ - 2P²Q² = 0

(p²-q²)²=0

p²-q² =0

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