Question

if p²x²-q²= 0 ,then X=​

Answer 1

Answer:

x= q/p

Step-by-step explanation:

p²x²-q²=0

p²x²=q²

x²=q²/p²

x=±q/p ( the square of an integer and it's additive inverse is same)for example 2²=4 and also, (-2) ²=4

Answer 2

${p}^{2} {x}^{2} - {q}^{2} = 0 \\ {p}^{2} {x}^{2} = {q}^{2} \\ {x}^{2} = \frac{ {q}^{2} }{ {p}^{2} } \\ x = + or - \: \sqrt{ \frac{ {q}^{2} }{ {p}^{2} } } \\ x = + or - \: ( \frac{q}{p} )$