if pa&pb are tangents to a circle with centre o such that <apb=50°, then find <aob
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Answer:
ans is 130°
Step-by-step explanation:
see the angle apb is 50 degree amd the other two corners except angle aob makes 90 ° each coz they are tangents so ,
<aob + <apb + 90 +90 = 360 °. [ANGLE SUM PROPERTY OF A QUADRILAERTAL]
so <aob = 360 - ( 90+90+50)
=130° ans
hope it helps
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