If PA and PB are tangents from an outside point P . such that PA = 10cm and angle APB = 60° . Find the length of chord AB.
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PA = PB (tangents from an external point are equal)
=> ∆PAB is isosceles.
=> Angle PAB = Angle PBA = 60° [all angles are 60° since two angles are 60° so remaining angle = 180°-(60°+60°) = 60°]
=> ∆ PAB is equilateral.
Hence, AB is 10 cm
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