Question

if pa and pb are tangents. prove that aop=2apo if the centre is o.​

Answer 1

Answer:

Step-by-step explanation:

oa=ob (radii)

op=po (common)

ap=pb (tangents from outside)

ΔOAP≅ΔOBP   (by SSS)

(by CPCT)

∠APO=∠BPO ---1

∠AOP=∠BOP----2

(from 1 and 2)

∠aop= 2∠apo

Answer 2

Answer:

Step-by-step explanation:

OA =OB

OP=PO

AP=PB

ΔOAP≅ΔOBP  

∠APO=∠BPO ---1

∠AOP=∠BOP----2

(from 1 and 2)

∠aop= 2∠apo