If PA= PB and the coordinates of A and B are (2,0) and (-2,4) and P lies on axis of Y, then find the coordinates of P.
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Please explain ... That -8y
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Here you have to keep in mind about the property of the Y axis which is that x=0 on Y axis.
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Coordinates of A and B are : (2,0) and (-2,4).
We have to find the coordinates of P.
Let it be P(0,y)[Because P lies on Y-axis, so x - axis will be 0]
It is said PA = PB
=> √(x₂ - x₁) ² + (y₂ - y₁)² = √(x₂ - x₁) ² + (y₂ - y₁)²
=> √(2 - 0)² + (0 - y)² = (-2 - 0)² + (4 - y)²
Squaring on both sides,
=> 4 + y² = 4 + (4 - y)²
(a - b)² = a² + b² - 2ab
=> 4 + y² = 4 + (4)² + (y)² - 2(4)(y)
=> 4 + y² = 4 + 16 + y² - 8y
=> 8y = 16
=> y = 2
Thus, coordinates are P(0,2)
#BeBrainly
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