Question

if pa=qb=rc and pqr=1 prove that 1/a+1/b+1/c=0

Answer 1

Changes made to your input should not affect the solution:

 (1): "t1"   was replaced by   "t^1". 

(2): Dot was discarded near "1.p".

Unauthorized use of the imaginary unit "i" or syntax error in complex arithmetic expression

... V ifpa=qb=rcandpqr=1provethat^1/a+1/b+1/c=0
The symbol "i" is only allowed in complex arithmetic, for example:
     (3/5+7i)+(0.3-7.002i) 
     (5+77i)-(19/4-8i) 
     (240-22i)*(247/7+2.222i) 
     (33/5+99i)/(33/5-88i) 

Too Many Equal Signs 

.......... V ifpa=qb=rcandpqr=1provethat^1/a+1/b+1/c=0

Too Many Equal Signs 

................... V ifpa=qb=rcandpqr=1provethat^1/a+1/b+1/c=0

Too Many Equal Signs 

.......................................... V ifpa=qb=rcandpqr=1provethat^1/a+1/b+1/c=0

Too Many Variables

.................... V i*f*p*a=q*b=r*c*a*n*d*p*q*r=1*p*r*o*v*e*t*h*a*t^1/a+1/b+1/c=0 Program Execution Terminated

Tiger was not able to solve for your input:ifpa=qb=rcandpqr=1.provethat1/a+1/b+1/c=0

Submit your own solution!

Answer 2

this is your answer