Question

If Pand Q are the zeroes of 2x^2-5x+8, then the value of (p^2+q^2) is​

Answer 1

SOLUTION

GIVEN

P and Q are the zeroes of 2x² - 5x + 8,

TO DETERMINE

The value of P² + Q²

EVALUATION

Here it is given that P and Q are the zeroes of 2x² - 5x + 8

This gives

Sum of the zeroes = P + Q = 5/2

Product of the Zeros = PQ = 4

Thus we get

$\sf{{P}^{2} +{ Q}^{2} }$

= (P + Q) ² - 2PQ

= 25/4 - 8

= - 7/4

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Answer 2

Given :  p and q are the zeroes of 2x²-5x+8,

To Find:  The  value of (p^2+q^2  )

Solution:

p² + q²  = (p + q)² - 2pq

2x²-5x+8,

Sum of zeroes = p + q =  - (-5)/2 = 5/2

Product of zeroes = pq = 8/2  = 4

p² + q²  = (p + q)² - 2pq

=> p² + q²  =  (5/2)² - 2(4)

=> p² + q²  =  25/4 - 8

=> p² + q²  =  -7/4

Value of p² + q²  is - 7/4

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