Question

If parallel sides of a trapezium is 6cm, 10cm and distance between them is 5cm then area is​

Answer 1

Answer:

Area = 40$cm^{2}$

Step-by-step explanation:

According to the information provided in the question it is given as

Parallel sides of a trapezium = 6 cm, 10 cm

Distance between them i= 5 cm

We need to find the area

First understand the shape trapezium

A trapezium is a convex quadrilateral with exactly one pair of opposite sides parallel to each other. The trapezium is a two-dimensional

A = a+b /2 x h

Where a=base =6 cm

            b= base = 1 cm

            h= height= 5 cm

As parallel sides means Base which is parallel to each other  and distance is nothing but the height between them

Now substituting the values we get the area

[tex]A = \frac{a+b}{2} \times h\\ A = \frac{6+10}{2} \times 5\\ A = \frac{16}{2} \times 5\\ A= 8\times 5\\ A = 40 cm^{2} [/tex]

So area of trapezium is 40$cm^{2}$

Answer 2

Given, In a Trapezium

Parallel sides that is a = 6cm , b = 10cm

and, Distance between Parallel sides that is

Height (h) = 5cm

Find the Area of Trapezium

▪Solution :-

Let's solve this problem by using, the formula,

$\boxed{\textbf{\textsf{\color{orange}Area \: of \: Trapezium \pink= \color{green}[(a + b)÷2] ∗ h}}}$

on substituting the values,

$\rm⇢ \: \: Area_{(Trapezium)} = \frac{(6 + 10)}{2} \times 5$

$\rm⇢ \: \: Area_{(Trapezium)} = \frac{16}{2} \times 5$

$\rm⇢ \: \: Area_{(Trapezium)} = 8 \times 5$

$\textbf{ \textsf{\red⇢ \boxed{ \textbf{\color{darkgreen}Area \: of \: \: Trapezium \blue= \orange{40 sq.cm}}}}}$

▫FINAL ANSWER :-

✏ Area of Trapezium = 40cm²