. If parallel sides of TRAPEZIUM are 10m and 14m and height is 4m ,its area is
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Let ABCD be a trapezium with,
AB∥CD
AB=25m
CD=10m
BC=14m
AD=13m
Draw CE∥DA. So, ADCE is a parallelogram with,
CD=AE=10m
CE=AD=13m
BE=AB−AE=25−10=15m
In ΔBCE, the semi perimeter will be,
s=2a+b+c
s=214+13+15
s=21m
Area of ΔBCE,
A=s(s−a)(s−b)(s−c)
=21(21−14)(21−13)(21−15)
=21(7)(8)(6)
=7056
=84m2
Also, area of ΔBCE is,
A=21×
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