if parallel sides of trapezium are 4and 5 and diagonals are7 find the area of trapezium in short trick
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Given
AB =4cm
DC = 5cm
AC = BD =7cm
Construction
AE is the height on DC
∆AEC,
AC^2 = AE^2 + EC^2
(7)^2 = AE^2 + (5)^2
49 - 25 = AE^2
24 = AE^2
2√6 = AE
4.898 ~ 5cm = AE
Area of trapezium = 1/2 h[a+b]
= 1/2 × 5× [4+5]
= 22.5cm^2
AB =4cm
DC = 5cm
AC = BD =7cm
Construction
AE is the height on DC
∆AEC,
AC^2 = AE^2 + EC^2
(7)^2 = AE^2 + (5)^2
49 - 25 = AE^2
24 = AE^2
2√6 = AE
4.898 ~ 5cm = AE
Area of trapezium = 1/2 h[a+b]
= 1/2 × 5× [4+5]
= 22.5cm^2
nishant85:
EC IS NOT 5. answer is 19.6 so please retry
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