If particle is thrown with 50m/sec upwards.Time taken by it to return
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time taken to reach topmost point 5s
chris2010shiva:
as v=u+at and v=0 at topmost point
and a=-g=-10m/s^2
we get distance thrown by using s=ut+(0.5)at^2
substituting t=5 and u=50 we get s=375m
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take taken to reach topmost point 5s.....
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