Math, asked by bubu38257, 5 months ago

If Pawan borrowed an amount of ₹14000 from Rahul with simple interest rate of 8%per annum for 2 years. What extra money should he pay if this sum is compounded with same interest rate and time period?

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Answered by parthiban777
14

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A man borrowed Rs. 40,4000 at 8% simple interest per year. At the end of second year he paid back certain amount and at the end of fifth year he paid back certain amount and at the end of fifth year he paid back Rs. 95960 and cleared the debt. What is the amount that he paid back after the second year?

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ANSWER

For the first two years,

Amount =40000+

100

40000×8×2

=40000+6400= Rs. 46400

Let x be the principal for the last 3 years.

Then, x+

100

x×8×3

=35960

⇒x+

25

6x

=35960

25

25x+6x

=35960

25

31x

=35960

⇒x=

31

35960×25

= Rs. 29000

∴ Amount paid back after the second year = Rs. 46400− Rs. 29000= Rs.17400.

Answered by subas77
8

Answer:

Step-by-step explanation:

If Pawan borrowed an amount of Rs.14,000 from Rahul with simple interest rate of 8% per annum for 2 years. What extra money should he pay if this sum is compounded with same interest rate and time period?

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